InterviewSolution
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InterviewSolution
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A box is projected up a long ramp (incline angle with the horizontal=30^(@)) with an initial speed of 8m/s. if the surface of the ramp is very smooth (essentially frictionless), how high up the ramp will the box go? What distance along the ramp will it slide? |
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Answer» Solution :Because friction is negligible, we can apply conservation of mechanical ENERGY. Calling the BOTTOM of the ramp our H=0 reference level, we write `K_(i)+U_(i)=K_(f)+U_(f)` `(1)/(2)mv_(0^(2)+0=0+mgh` `h=((1)/(2)v_(0)^(2))/(g)` ltBrgt `=((1)/(2)(8m//s)^(2))/(10m//s^(2))` =3.2m Since the INCLINE angle is `theta=30^(@)`, the distance, d, it slides up the ramp is found in the following way.  `h=dsintheta` `d=(h)/(sintheta)=(3.2m)/(sin30^(@))=6.4m`. |
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