1.

A box of mass 40 kg is pusched in a straight line across a horizontal floor by an 80 N force. If the force of kinetic friction acting on the box has a magnitude of 60 N, what is the acceleration of the box?

Answer»

`0.25m//s^(2)`
`0.5m//s^(2)`
`1.0m//s^(2)`
`2.0m//s^(2)`

Solution :The net FORCE acting on the BLOCK is 80N-60N=20N. DIVIDING the net force by the object's mass gives the acceleration (Newton's second law), so we find that `a=F_("net")//m=(20N)//(40kg)=0.5m//s^(2)`.


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