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A box with a mass of 2kg accelerates in a straight line from 4 m/s to 8m/s due to the application of a force whose duration is 0.5 s. find the average strength of this force. |
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Answer» 2N `overline(F)Deltat=Deltap=p_(f)-p_(i)=m(v_(f)-v_(i))implies overline(F)=(m(v_(f)-v_(i)))/(Deltat)=((2kg)(8m//s-4m//s))/(0.5s)=16N` |
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