1.

A box with a mass of 2kg accelerates in a straight line from 4 m/s to 8m/s due to the application of a force whose duration is 0.5 s. find the average strength of this force.

Answer»

2N
4N
8N
16N

Solution :The impulse delivered to the ball,`J=overline(F)Deltat`, equals its CHANGE in MOMENTUM. Thus,
`overline(F)Deltat=Deltap=p_(f)-p_(i)=m(v_(f)-v_(i))implies overline(F)=(m(v_(f)-v_(i)))/(Deltat)=((2kg)(8m//s-4m//s))/(0.5s)=16N`


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