1.

A boy and a man carry a uniform rod of length L,horizontally in such a way that the boy gets (1)/(4)th of the load. If the boy is at one end, the distance of the man from the other end is :

Answer»

L/4
L/3
2 L/3
2 L/4

Solution :Let the man be at a distance x from ONE end of rod.

`:.`TAKING momentum about center of gravity, we have
`(-W)/(4)xxL/2+(3W)/(4)(L/2-x)=0`
`(WL)/(4xx2)=(3W)/(4)(L/2-x)`
`L/2=(3L)/(2)-3ximplies3x=(3L)/(2)-L/2implies3x=Limpliesx=L/3`


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