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A boy and a man carry a uniform rod of length L,horizontally in such a way that the boy gets (1)/(4)th of the load. If the boy is at one end, the distance of the man from the other end is : |
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Answer» L/4 `:.`TAKING momentum about center of gravity, we have `(-W)/(4)xxL/2+(3W)/(4)(L/2-x)=0` `(WL)/(4xx2)=(3W)/(4)(L/2-x)` `L/2=(3L)/(2)-3ximplies3x=(3L)/(2)-L/2implies3x=Limpliesx=L/3` |
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