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InterviewSolution
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A boy is standing on the top of a tower 100 m high. He throws a packet with a horizontal velocity of 10m * s ^ - 1 to his friend standing on the ground, 200 m away from the foot of the tower. Will the packet reach to his friend ? If not, how short will the packet full ? |
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Answer» From the figure, Tanθ=171/228 θ=Tan⁻¹[171/228] The motion of projectile is from point A. Take reference axis at a. θ=37° as u is below X axis. u=15ft/s g=32.2ft/s2 y=-171ft From y= Tanθ-x²gsec²θ/2u² -171=(tan37°)x- x²x32.2x(1.568)/2x225 -171=0.7536x- 0.1125x² 0.1125x²-0.7536x-171=0 on solving we can get x=35.78ft Horizontal RANGE covered by packet is 35.8ft . So the packet will fall =228-35.8=192ft SHORT of his friend. EXPLANATION:hope u have been understood MARK me as brainlist |
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