1.

A boy of mass 40 kg is climbing on a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is 0.8 and g = 10 m//s^(2), the horizontal force that he is applying on the pole is

Answer»

300 N
400 N
500 N
600 N

Solution :Here,`mu`= 0.8
LET F be horizontal force that the BOY is APPLYING on the pole. The various forces are acting on the boy as shown in the figure.
FRICTIONAL force,f= μN= mg
`N=(mg)/(mu)=(40xx10)/(0.8)=500N`
F=N=500N


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