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A boy of mass 60 kg standing on a plat-form of mass 40 kg placed over a smooth horizontal surface. He throw, a stone of mass 1 kg with velocity u - 10 m/s at on angle of 45° w.r.t the ground. The displacement of platform (with boy) on the horizontal surfaces when the stone lands on the ground is (g = 10 m//s^(2)) |
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Answer» Solution :`1 xx u COS 45^(@) =(60 + 40) v, v=1/(10sqrt(2))` TIME of flight, `T_(f) =(2u SIN theta)/G = sqrt(2)` sec. `S = v xx T_(f) =0.1` m |
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