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A boy of mass 60 kg standing on a platform of mass 40 kg placed over a smooth horizontal surface. He throw, a stone of mass 1 kg with velocity u = 10 m/s at on angle of 45^(@) w.r.t the ground. The displacement of platform (with boy) on the horizontal surface when the stone lands on the ground is (g=10 m//s^(2)) |
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Answer» SOLUTION :`1 u cos 45^(@)=(60+40)v , v=(1)/(10sqrt(2))` Time of FLIGHT `= T_(f)=(2U sin theta)/(g)=sqrt(2)sec`. `S= v XX T_(f)=0.1 m` |
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