1.

A boy throws a ball in air in such a manner that when the ball is in its max. height, he throws another ball. If the balls are thrown after the time difference of 1 s, then what will be the height attained by them:

Answer»

19.6 m
9.8 m
4.9m
2.45 m

Solution :SINCE t=1 s`:. H=(1)/(2)G t^(2)=(1)/(2)xx9.8xx12=4.9 m`


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