1.

A brass wire of length 5 m and cross section area 10^(-6) m^(2) hungfrom rigidsupportwith brass weight of volume 10^(-3)m^(3) hangingfrom other end. Then the decreasein length of the wire when brassweight is completely immersed in water is, (g=10m//s^(2), Y_("brass")=10^(11)N//m^(2), rho_(w)=10^(3)kg//m^(3))

Answer»

`5xx10^(-4)m`
`3XX10^(-4)m`
`4XX10^(-4)m`
`2xx10^(-2)m`

Solution :`l_(1)-l_(2)=(F_(1)-F_(2))(L)/(Ay)=(V RHO GL)/(AY)`


Discussion

No Comment Found

Related InterviewSolutions