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A bright fringe is formed in front of one of the double slits. What will be the fringe width of the interference pattern? |
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Answer» Solution :`BETA=(lambda D)/(d)` and `X=n beta` for `C.I.` Here, `x=(d)/(2) and n=1` or `lambda=(d^2)/(2D)` and the fringe width `beta=(lambda d)/(2)`. |
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