1.

A broad source of light lambda = 6800 Å illumintates normally two glass plates 12 cm long. They touch at one end and are separated by a wire 0.048 mm. In diameter at the other end.How many bright fringes appear over the 12 cm. Distance.

Answer»

141
120
101
151

Solution :
For bright fringes FORMED by a gap of wedge due to LIGHT incident normally
`2d = (n+1/2)lambda`
Here d = 0.0048 CMS
diameter of WIRE (an gap) at the point where NTH fringe is formed.
`therefore n = (2d)/(lambda) -1/2`
`= (2 xx 0.0048)/(6800 xx 10^(-8) -1/2`
= 141


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