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A broad source of light lambda = 6800 Å illumintates normally two glass plates 12 cm long. They touch at one end and are separated by a wire 0.048 mm. In diameter at the other end.How many bright fringes appear over the 12 cm. Distance. |
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Answer» 141 ![]() For bright fringes FORMED by a gap of wedge due to LIGHT incident normally `2d = (n+1/2)lambda` Here d = 0.0048 CMS diameter of WIRE (an gap) at the point where NTH fringe is formed. `therefore n = (2d)/(lambda) -1/2` `= (2 xx 0.0048)/(6800 xx 10^(-8) -1/2` = 141 |
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