

InterviewSolution
Saved Bookmarks
1. |
A brown ring is formed in the ring test for `NO_(3)^(-)` ion. It is due to the formation ofA. `[Fe(H_(2)O)_(5)(NO)]^(2+)`B. `FeSO_(4)cdot NO_(2)`C. `[Fe(H_(2)O)_(4)(NO)_(2)]^(2+)`D. `FeSO_(4)cdot HNO_(3)` |
Answer» Correct Answer - A `NO_(3)^(-)+3Fe^(2+)+4H^(+)rarrNO+3Fe^(3+)+2H_(2)O` `[Fe(H_(2)O)_(6)]^(2+)+NOrarrunderset("(Brown)")([Fe(H_(2)O)_(5)(NO)])^(2+)+H_(2)O` |
|