1.

A brown ring is formed in the ring test for NOg ion. It is due to the formation of

Answer»

`[Fe(H_(2)O)_(5) (NO)]^(2+)`
`FeSO_(4).NO_(2)`
`[Fe(H_(2)O)_(4)(NO)_(2)]^(2+)`
`FeSO_(4).HNO_(3)`

SOLUTION :`[Fe(H_(2)O)_(6)]^(2+) + NO tounderset("Brown ring")([Fe(H_(2)O)_(5)(NO)]^(2+) + H_(2)O)`


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