1.

A bubble of air is underwater at temperature 15^(@)C and the pressure 1.5 bar. If the bubble rises to the surface where the temperature is 25^(@)C and the pressure is1.0 bar, what will happen to the volume of the bubble?

Answer»

Volume will become GREATER by a factor of 1.6
Volume will become greater by a factor of 1.1
Volume will become smaller by a factor of 0.70
Volume will become greater by a factor of 2.5

Solution :WE know that from IDEAL EQUATION
`Vprop T/P`
Given `T_(1)=15+273=287, P_(1)=1.5` BAR
`T_(2)=25+273=298, P_(2)=1` bar
`V_(1)prop 288/1.5` i.e. `V_(1)prop 192`
`V_(2)prop 298/1implies(V_(2))/(V_(1))=298/192=1.55~~1.6`


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