InterviewSolution
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InterviewSolution
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A bucket of water is whirled in a vertical circle at an arm’s length. Find the minimum speed at the top so that no water spills out. Also find the corresponding angular speed. [Assume r = 0.75 m] |
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Answer» Data : r = 0.75 m, g = 10 m/s2 At the highest point the minimum speed required is v = \(\sqrt{rg}\) = \(\sqrt{0.75\times 10}\) = 2.738 ω = \(\frac{v}r\)= \(\frac{2.738}{0.75}\) = 3.651 rad/s |
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