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A bulb of constant volume is attached to a manometer tube open at other end as shown in figure. The manometer is filled with a liquid of density `(1//3)^("rd")` that of mercury. Initially h was 228 cm. Through a small hole in the bulb gas leaked assuming pressure decreases as `(dP)/(dt)=-kp.`If value of h is 114 cm after 14 minutes, what is the value of k (in `"hour"^(-1)`)? [ Use : In (4/3) =0.28 and density of Hg =13.6 g/mL.].A. 0.6B. 1.2C. 2.4D. none of these

Answer» Correct Answer - b
(b) `P=P_(0^(e^(-kt))),P_(0)=(228)/(3)+76=152cm Hg`
`"At "t=14 min,P=(114)/(3)+76=114cm Hg`
`implies" "152e^(-kt)=114`
`impliesk=(1)/(t)"In"(152)/(114)=(1)/(14)xx0.28`
`=0.02xx60hr^(-1)=1.2hr^(-1)`


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