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A bulb of unknown volume contained an ideal gas at 650 mm pressure. A certain amount of gas was withdraw and found to occupy 1.52 cc at 1 atm pressure. The pressure of the gas remaining in the bulb was 600 mm. If all measurements were made at a constant temperature, find the volume of the bulb. |
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Answer» SOLUTION :When a certain amount of the gas is WITHDRAWN, the pressure dropped from 650 mm to 600 mm. So the pressure difference (650 - 600) ot 50 mm will be the pressure of the gas withdrawn which occupied the bub of volume `V_(1)` cc (suppose). SINCE the same amount of withdrawn gas occupied 1.52 cc at 1 atm (760 mm) pressure at the same TEMPERATURE, we can apply Boyle.s law : `p_(1)V_(1) = p_(2)V_(2)` `50 xx V_(1) = 760 xx 1.52` `V_(1) = 23.1` cc. |
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