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A bullet fired into a fixed target loses 20% of its K.E.in penetrating 1 cm. Find the total distance penetrated by bullet before it comes to rest : |
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Answer» 2 cm or`v^2=4/5u^2` APPLYING `v^2-u^2=2aS,4//5u^2=u^2-2axx1` or `a=(u^2)/(10)`. LET .X. be the distance penetrated.When bullet comes to rest i.e v=0, then `:. 0=u^2-2(u^2/10)x` or x=5 cm. |
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