A bullet fired into a fixed target loses half of its velocity after penetrating 3 cm. How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion ?

A bullet fired into a fixed target loses half of its velocity after pe

1.	A bullet fired into a fixed target loses half of its velocity after penetrating 3 cm. How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion ?
Answer» 3.0 CM 2.0 cm 1.5 cm 1.0 cm Solution :Let K be the initial KINETIC enrgy and f be the resistive force. `DELTAK`= work done against f. `1/2m[v^2-(v^2)/(4)]=fxx3` `1/2m[(v^2)/(4)-0]=fxx x` Dividing `([1-1/4])/(1/4)=3/x` or x=1 cm.

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A bullet fired into a fixed target loses half of its velocity after penetrating 3 cm. How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion ?

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