InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A bullet fired into a fixed target loses half of its velocity after penetrating 3cm. How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion? |
|
Answer» Let `m` be the mass of bullet and `upsilon` be its initial velocity. If `F` is constant resistance to motion, then `(i)` Work done `=` loss in KE `=` force `xx` distance `=(1)/(2) m(upsilon^(2)-(upsilon^(2))/( 4))=Fxx3` or `(1)/(2) m ( (3 upsilon^(2))/(4))=Fxxs ....(i)` `(ii)` Work done `=` loss in KE `=` force `xx` distance `=(1)/(2) m ( (upsilon^(2))/( 4)-0)=Fxxs...(ii)` Dividing `(ii)` and `(i)`, we get `(1)/(3) =(s)/(3)` `:. s = 1 cm` |
|