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A bullet moving with a velocity of 800 ms^(-1) strikes two wooden plates of width x_(1) and x_(2) and in pasing through each of them loses 200 ms^(-1) of its velocity. Assuming the resistance of the plates to be uniform the ratio n_(1)//n_(2) is : |
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Answer» 15/13 `:. (1/2m(800^(2)-600^(2)))/(1/2m(600^(2)-400^(2)))=(Fx_(1))/(Fx_(2))` `:. (x_(1))/(x_(2))=(1400xx200)/(1000xx200)=7/5` |
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