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A bullet of mass 10 g moving with a velocity `300 ms^(-1)` strikes a wooden block and comes out from ot her side with a velocity of `200ms^(-1).` Find the work done by t he resistive force on the bullet. |
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Answer» `DeltaK=K_(f)-K_(i)=W` `W=1/2mv ^(2)mu^(2).m=10xx10^(-3)kg,u=300m//sv=200m//s` `W=K_(f)-K_(f)=1/2mv^(2)-1/2mu^(2)=1/2xx10xx10^(-3)xx(200^(2)-300^(2))` `=-5xx10^(-3)xx500x100=-250J` |
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