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A bullet of mass 10 moving horizontally witha velocity of 400 m/s |
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Answer»
↪FOLLOW , BRAINLIST ME☺☺PLZZ ✌✌✌✌✌✌✌✌✌ Ur Question uncomplete further I am giving ANSWER I think you ASKING for IMPULSE in 0.1 secV= u +at 0 =400 + 0.1×a a= -4000 m/s^2 Now impulse= F×t = 10×(4000)×0.1 =4000 Ns |
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