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A bullet of mass 50 g is fired from a gun. If the bullet acquires a velocity of 100 m `s^(1)` in 0.1 second, what is the recoil force on the gun? |
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Answer» Mass of bullet, m = 50 g = `50 xx 10^(-3)` kg Initial velocity of the bullet, u = 0 m `s^(-1)` Final velocity of the bullet, v = 100 m `s^(-1)` Time, t = 0.1 s Force exerted on the bullet, `F = ma = m[(v-u)/(t)]` `=50 xx 10^(-3) ((100-0)/(0.1)) = 50N` This is the action on the bullet Thus, reaction on the gun = 50 N `therefore` The recoil force on the gun = 50 N |
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