1.

A bullet on penetrating 30 cm into its target loses its velocity by 50%. What additional distanee will it penetrate into the target before it comes to rest?

Answer»

30 cm
20 cm
10 cm
5 cm

Solution :For lirst part of PENCTRATION, by cquation of motion `((nu)/(2))^(2)-(nu)^(2)=2a(30xx10^(-2))`
`a = -(3nu^(2))/(8(30xx10^(-2)))`
For latter part of PENETRATION by EQUATION of motion
`0-((nu)/(2))^(2)=2ax`
`X= -(nu^(2))/(8A)`
`= (nu^(2))/(8) ((8(30xx10^(-2)))/(-3nu^(2)))"" `(Using (i))
`= 10xx10^(-2)m = 10cm`


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