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A bullet weighing 10 g is fired with a velocity of 800 ms-1. After passing through a mud wall 1 m wall thick, its velocity decreases to 100 ms-1. Find the average resistance offered by the mud wall. |
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Answer» Using F.s = \(\frac{1}{2}mv^2-\frac{1}{2}mu^2\) where m = 10 g = \(\frac{10}{1000}\)kg = 0.01 kg and v = 100 ms-1 , u = 800 ms-1 and s = 1 m, we get F = \(\frac{1}{2}\) × 0.01 × (1002 − 8002) = −3150 N. |
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