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A buring candle is placed in front of a concave spherical mirror on its principal optical axis at a distance of (4//3)F form the pole of the mirror (here F is the focal length of the mirror). The candle is arranged at right angle to the axis. The image of the candle in the concave mirror impinges upon a convex mirror of focal length 2F . The distance between the mirrors is 3F and their axescoincide. The image of the candle in the first mirror plays the part of a virtual object with respect to the second mirror and gives a real image arranged between the two mirrors. Find the total linear magnification (magnitude only) of the system. |
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Answer» `(1)/(-F)=(1)/(v)+(1)/(-4F//3)` `rArr v=-4F` Hence `m_(1)=(-v)/(u)=-3` For reflection by concave mirror, `u=F , f=+2F (1)/(2F)=(1)/(v)+(1)/(F)(1)/(v)=(1)/(2F)-(1)/(F)=-(1)/(2F)v=-2F` magnification by concave mirror. `m_(2)=-(-(2F)/(F))=2` Net magnification `=m_(1)m_(2)=(-3)(2)=-6` 
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