A bus is travelling at speed of 15m/s. Then it accelerates for 5s at a rate of 10m/s2. Find the final velocity and distance covered by the bus during this process.

A bus is travelling at speed of 15m/s. Then it accelerates for 5s at a

1.	A bus is travelling at speed of 15m/s. Then it accelerates for 5s at a rate of 10m/s2. Find the final velocity and distance covered by the bus during this process.
Answer» -The speed of the bus = 15m/sThe acceleration of bus = 10m/s²Time TAKEN by the bus = 5sTo Find :-The FINAL velocity of bus (v) = ?The distance covered by the bus (s) = ?Solution :-To calculate the final velocity of bus and distance travelled by the bus , at first we have to use first equation of motion to calculate final velocity of the bus then calculate distance travelled by the bus by applying 2NS equation of motion.Calculation for Final velocity :-V = ? U = 15m/s. T = 5s. A = 10m/s² :-⇢ First equation of motion :-⇢ V = U + A × T⇢ V = 15 + 10 × 5⇢ V = 15 + 50⇢ V = 65m/sTherefore, final velocity of the bus (v) = 65m/sCalculation for Distance covered by bus :-S = ? U = 15m/s. T= 5s. A = 10m/s²⇢ 2nd equation of motion :-⇢ S = UT + 1/2 × A × T²⇢ S = 15 × 5 + 1/2 × 10 × 5²⇢ S = 75 + 5 × 25⇢ S = 75 + 125⇢ S = 200mTherefore, distance covered by the bus (s) = 200m