A bus starts from rest with an acceleration of 1 m//s^(2) A man who is 48 m behind the bus starts with a uniform velocity of 10 m s^(-1). Then after how much time the man will catch the bus ?

A bus starts from rest with an acceleration of 1 m//s^(2) A man who is

1.	A bus starts from rest with an acceleration of 1 m//s^(2) A man who is 48 m behind the bus starts with a uniform velocity of 10 m s^(-1). Then after how much time the man will catch the bus ?
Answer» 12 s 8s 10 s 4s Solution :Let them meet in t second. Distance coverede by bus in t second x=ut`(1)/(2) at^(2)=0+(1)/(2)1xxt^(2)` Disatnce COVERED by man in t `s=10xxt` `:. 10t=48+(1)/(2)t^(2)implies t=8` s.

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A bus starts from rest with an acceleration of 1 m//s^(2) A man who is 48 m behind the bus starts with a uniform velocity of 10 m s^(-1). Then after how much time the man will catch the bus ?

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