1.

A bus starts moving with an acceleration2 ms? A cyclist 96 m behind the bus starts simultaneously towards the bus at 20 m s-, after what time will he able to overtake the bus?

Answer»

4 s
8 s
12 s
16 s

Solution :Here `96+(1)/(2)rt^(2)`=Total distance to be COVERED by the cyclist.
ALSO total distance covered bythe cylist =20.t
`:. 20.t=(1)/(2)xx2t^(2)+96`
or `t^(2)-20t+96`
`t=(20pmsqrt(400-384))/(2)`
`t=(20pm4)/(2)=12sec,8sec`
Minimum time =8 sec


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