1.

A bus travelling the frist one third distance at speed of 10 km/h the next one fourth 20 km/ h and remaining at 40 km/ h what is the average speed of the path

Answer»

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If total distance is S then

Average speed = Total distance / Time= S / (t1 + t2)= S / [(S/(3 * 10)) + (S/(4 * 20)) + (5S/(12 * 40))] ...….....[∵ Time = Distance / Speed]= 1 / (1/30 + 1/80 + 5/480)= 17.7 kmph

In two significant figures average speed will be 18 kmph

18kmph is the answer of the

18 is the correct answer of the given question



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