A businessman instituted an annual awardin a city school, with a part

1.	A businessman instituted an annual awardin a city school, with a part of the awardgiven to the school itself to improve itsfacilities. It was stated that if a student froma wealthy family were to top the annualexamination, the school would receivetwice the amount awarded to the student.On the other hand, if a student from a poorfamily were to top the annual examination,the student would be awarded twice theamount that the school would receive. Inone year, two students, one rich and onepoor, jointly topped the annual examination.What fraction of the award money did theschool receive in this case?
Answer» Answer: The poor student gets (1/3) of the prize money. The rich student gets (1/6) of the prize money. Step-by-step explanation: LET N be the amount of the prize money. With RESPECT to the rich student, the prize money gets divided into a 1:2 ratio. So the rich student gets 1/3 of N/2 = (1/6)N and the SCHOOL gets (2/3) of N/2 = (1/3)N The OPPOSITE is true for the poor student. So the prize money is divided as follows: (1/6)N goes to the rich student (1/3)N+(1/6)N = (3/6)N = (1/2)N goes to the school (1/3)N goes to the poor student So the school gets half of the price money. The poor student gets (1/3) of the prize money. The rich student gets (1/6) of the prize money. Hope it HELPS!!

A businessman instituted an annual awardin a city school, with a part of the awardgiven to the school itself to improve itsfacilities. It was stated that if a student froma wealthy family were to top the annualexamination, the school would receivetwice the amount awarded to the student.On the other hand, if a student from a poorfamily were to top the annual examination,the student would be awarded twice theamount that the school would receive. Inone year, two students, one rich and onepoor, jointly topped the annual examination.What fraction of the award money did theschool receive in this case?

Answer»

Answer:

The poor student gets (1/3) of the prize money.

The rich student gets (1/6) of the prize money.

Step-by-step explanation:

LET N be the amount of the prize money.

With RESPECT to the rich student, the prize money gets

divided into a 1:2 ratio.

So the rich student gets 1/3 of N/2 = (1/6)N

and the SCHOOL gets (2/3) of N/2 = (1/3)N

The OPPOSITE is true for the poor student.

So the prize money is divided as follows:

(1/6)N goes to the rich student

(1/3)N+(1/6)N = (3/6)N = (1/2)N goes to the school

(1/3)N goes to the poor student

So the school gets half of the price money.

The poor student gets (1/3) of the prize money.

The rich student gets (1/6) of the prize money.

Hope it HELPS!!