InterviewSolution
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InterviewSolution
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A cage of mass M hangs from a light spring of force constant `k`. A body of mass m falls from height h inside the cage and stricks to its floor. The amplitude of oscillations of the cage will be- A. `((2mgh)/(k))^(1//2)`B. `((k)/(2mgh))^(1//2)`C. `(mg)/(k)`D. `((mg)/(k))^(1//2)` |
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Answer» Correct Answer - A `mgh = 1/2(M + m) v^(2) = 1/2 kx^(2)` `mgh = 1/2 kx^(2) rArr x = [(2mgh)/(k)]^(1//2)` |
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