InterviewSolution
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InterviewSolution
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A calorimeter of mass m contains an equal mass of water in it. The temperature of the water and clorimeter is `t_(2).A` block of ice of mass m and temperature `t_(3)lt0^(@)C` is gently dropped into the calorimeter. Let `C_(1),C_(2) and C_(3)` be the specific heats of calorimeter, water and ice respectively and `L` be the latent heat of ice. The whole mixture in the calorimeter becomes water ifA. `(C_(1)+C_(2))t_(2)-C_(3)t_(3)+Lgt0`B. `(C_(1)+C_(2))t_(2)+C_(3)t_(3)+Lgt0`C. `(C_(1)+C_(2))t_(2)-C_(3)t_(3)-Lgt0`D. `(C_(1)+C_(2))t_(2)+C_(3)t_(3)-Lgt0` |
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Answer» Correct Answer - D Heat lost `=mC_(1)(t_(2)-0)+mC_(2)(t_(2)-0)` Heat gained `=mC_(3)(0-t_(3))+mL` `:. C_(1)t_(2)+C_(2)t_(2)gtC_(3)t_(2)gtC_(3)t_(3)+L` `:. C_(1)t_(1)+C_(2)t_(2)+C_(3)t_(3)-L gt 0` |
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