InterviewSolution
Saved Bookmarks
| 1. |
A calorimeter will heat capacity equivalent to having `13.3` moles of water is used to measured the heat of combustion from `0.303 g` of sugar `(C_(12)H_(22)O_(11))`. The temperature increase was found to be `5.0 K`. Calculate the heat released, the amount of heat released by `1.0 g`, and `1.0` mole of sugar. |
|
Answer» Heat released, `q_(v)`, `q_(v)=13.3xx75.2xx5.0 K` `=5000 J` The amount of heat released by `1.0g` would be, `5000 J//0.303 g=16.5" kJ/g"` since the molecular weight of sugar is 342 h/mol, the amount of hear released by `1.0` mole would be `16.5xx342=56431" kJ/mol"`. |
|