1.

A can contains a mixture of two liquids A and B in the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. Litres of liquid A contained by the can initially was1). 102). 203). 214). 25

Answer»

Since the ratio of volume of LIQUIDS A and B is 7 : 5.

Let the volume of A in mixture initially be 7X lts and volume of B in mixture initially be 5x lts

Total volume in can initially = 12x lts

Since 9 lts were drawn off from total mixture and same was filled by liquid B. Thus,

New volume of liquid A = $(\left( {7x - \frac{9}{{12x}} \times 7x} \RIGHT))$

New volume of liquid B = $(\left( {5x - \frac{9}{{12x}} \times 5x + 9} \right))$

Given the new ratio of liquid A and B is 7 : 9. Thus,

$(\begin{array}{l} \Rightarrow \frac{{7x - \frac{9}{{12x}} \times 7x}}{{5x - \frac{9}{{12x}} \times 5x + 9}} = \frac{7}{9}\\ \Rightarrow \frac{{28x - 21}}{{20x - 15 + 36}} = \frac{7}{9} \end{array})$

⇒ 252x – 189 = 140x + 147

⇒ 112x = 336

⇒ x = 3

Hence the initial volume of liquid A = 7 × 3

= 21 liters


Discussion

No Comment Found

Related InterviewSolutions