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A can do a piece of work in 10 days m,B in 12 days and C in 15 days.All begin together but A leaves the work after 2 days and B leaves 3 days before the work is finished. How long did the work last. |
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Answer» Answer: 7 Step-by-step explanation: Efficiency , A : B : C = 6 : 5 : 4 Now , 4T + (T-3)*5 + 2*6 = 60 => 4T + 5T - 15 + 12 = 60 => 9T = 63 => T = 7 days (ANS.) |
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