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A canon ball is fired with a velocity 200 m^(-1) at an angle of 60^(@) with horizontal. At the highest point it explodes into 3 equal parts. One moves vertically upwards with 100 ms^(-1), second moves vertically downwards with 100 ms^(-1). The third moves with velocity : |
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Answer» `100 ms^(-1)` horizontally along horizontal `= 100 m//s` Let m be the MASS of each part. APPLYING conservation of momentum along x-axis.3m (100) `= m xxupsilon impliesupsilon= 300 m//s` Hence the correct choice is (b). |
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