1.

A canon ball is fired with a velocity 200 m^(-1) at an angle of 60^(@) with horizontal. At the highest point it explodes into 3 equal parts. One moves vertically upwards with 100 ms^(-1), second moves vertically downwards with 100 ms^(-1). The third moves with velocity :

Answer»

`100 ms^(-1)` horizontally
`300 ms^(-1)` horizonally
`200 ms^(-1)` making an angle of `60^(@)` with horizontal
`200 ms^(-1)` making an angle of `30^(@)`with horizontal.

Solution :Velocity at highest point,` upsilon=u COS theta = 200 cos 60^(@)`
along horizontal `= 100 m//s` Let m be the MASS of each part.
APPLYING conservation of momentum along x-axis.3m (100) `= m xxupsilon impliesupsilon= 300 m//s`
Hence the correct choice is (b).


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