1.

A capacitor has square plates each of side .a. making an angle small theta , the capacitance is given by:

Answer»

`C=(epsilon_0a^2)/d[1-(thetaa)/(2D)]`
`C=(epsilon_0a^2)/d[1-(thetaa)/(d)]`
`C=(epsilon_0a)/d^(2)[1-(thetaa)/(d)]`
`C=(epsilon_0a^2)/d`

ANSWER :A


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