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A capacitor is made of two circular plates each of radius 12 cm, and separated by 5.0 cm. The capacitor is being charged by an external source. The charging current is constant and equal to 0.15 A. (a) Calculate the capacitance and rate of change of potential difference between the plates. |
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Answer» Solution :`because V=Q/C` or , `(dV)/(dt)=1/C (DQ)/(dt)=I/C` In this CASE, `C=(in_0A)/d=(8.854xx10^(-12)xx3.14xx(12xx10^(-2))^2)/(5xx10^(-2))` `=8xx10^(-12)F`=8 pE `THEREFORE (dV)/(dt)=I/C=0.15/(8xx10^(-12))=1.875xx10^10 V.s^(-1)` |
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