A capacitor of 2 muF is charged to a potential of 4V using a battery, and then the battery is disconnected and the changed capacior is connected to an uncjharged caspacitor of 4 muF capacitance. When the equilibrium is established the total energy stored in the capacitors is

A capacitor of 2 muF is charged to a potential of 4V using a battery,

1.	A capacitor of 2 muF is charged to a potential of 4V using a battery, and then the battery is disconnected and the changed capacior is connected to an uncjharged caspacitor of 4 muF capacitance. When the equilibrium is established the total energy stored in the capacitors is
Answer» `16 muJ` `(16)/(3)muJ` `(32)/(3)muJ` `(32)/(9)muJ` SOLUTION :`V=(C_(1)V_(1)+C_(2)V_(2))/(C_(1)+C_(2))` `U_(F)=1/2(C_(1)+C_(2))V^(2)`

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A capacitor of 2 muF is charged to a potential of 4V using a battery, and then the battery is disconnected and the changed capacior is connected to an uncjharged caspacitor of 4 muF capacitance. When the equilibrium is established the total energy stored in the capacitors is

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