A capacitor of capacitance 10 muF is charged to 100 V. It is now connected to uncharged capacitor in parallel so that the common potential becomes 40 V. The capacitance of the second capacitor is

A capacitor of capacitance 10 muF is charged to 100 V. It is now conne

1.	A capacitor of capacitance 10 muF is charged to 100 V. It is now connected to uncharged capacitor in parallel so that the common potential becomes 40 V. The capacitance of the second capacitor is
Answer» `10 mu F` `5 mu F ` `15 mu F ` `25 mu F` Solution :Common potential `V = (C_1V_1 + C_2V_2)/(C_1 + C_2)`, hence `40 = ((10 MUF) xx 100V + C_2 xx0)/((10 mu F + C_2)) rArr C_2 = 15 muF`

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A capacitor of capacitance 10 muF is charged to 100 V. It is now connected to uncharged capacitor in parallel so that the common potential becomes 40 V. The capacitance of the second capacitor is

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