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A capacitor of capacitance `2 mu F` is connected in the tank circuit of an oscillator oscillating with a frequency of 1 kHz. If the current flowing in the circuit is `2 mA`, the voltage across the capacitor will beA. `0.32 V`B. `0.16 V`C. `79.5 V`D. `159 V` |
Answer» Correct Answer - B Reactance fo capacitor or capacitive reactance is given by `X_(C)=1/(omegaC)=1/(2pifC)` where `f` is frequency of the alternating current Given, `f=1xx10^(3)Hz, C=2xx10^(6)F` `:. X_(C)=1/(2xx3.14xx10^(3)xx2xx10^(-6))` `=(10^(3))/(4xx3.14)` Hence, voltage across the capacitor is `V=iX_(C)=2xx10^(-30xx(10^(3))/(4xx3.14)=0.16 V` |
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