1.

A capacitor of capacitance `2 mu F` is connected in the tank circuit of an oscillator oscillating with a frequency of 1 kHz. If the current flowing in the circuit is `2 mA`, the voltage across the capacitor will be

Answer» `V_(C ) = IX_(C ) = I xx (1)/(omega C) = (I)/(2 pi fC)`
`= (2 xx 10^(-3))/(2 pi xx 10^(3) xx 2 xx 10^(-6)) = 0.16 V`


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