

InterviewSolution
Saved Bookmarks
1. |
A capacitor of capacitance 250 pF is connected in parallel with a choke coil having inductance of `1.6 xx 10^(-2) H` and resistance `20 Omega`. Calculate (a) the resonance frequency and (b) the circuit impedance at resonance. |
Answer» a) The resonance frequency of a rejector L-C-R circut is given by `f=1/(2pi)sqrt(1/(LC) - R^(2)/L^(2))` `=1/(2pi)sqrt(1/((1.6xx10^(-2))(250xx10^(-12)))-(20)^(2)/(1.6xx10^(-2))^(2))`= `7.96 xx 10^(4) Hz` b) the circuit impedance at resonance is given by, `Z=L/(CR) = (1.6 xx 10^(-2))/(250 xx 10^(-12)xx(20))=3.2 xx 10^(6) Omega` |
|