1.

A capacitor of capacitance C_(0) is charged to a potential V_(0) and is connected with another capacitor of capacitance C as Shown . After closing the switch S, the common potential across the two capacitors becomes V . The capacitance C is given by

Answer»

`(C_(0)(V_(0)-V))/(V_(0))`
`(C_(0)(V-V_(0)))/(V_(0))`
`(C_(0)(V+V_(0)))/(V)`
`(C_(0)(V_(0)-V))/(V)`

ANSWER :d


Discussion

No Comment Found

Related InterviewSolutions