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A capacitor of capacitance C charged by an amount Q is connected in parallel with an uncharged capacitor of capacitance 2C. The final charges on the capacitors are

Answer»

`(Q)/(3) , (2Q)/( 3)`
`(Q)/(2) ,(Q)/(2)`
`(Q)/(5),(4Q)/(5)`
`(Q)/(4) ,(3Q)/(4)`

Solution :The TWO capacitor will reach a common potential. As the changes are in parallel combination.
`(Q_1)/(C )=(Q_2)/(2C ) implies2Q_1`
so ` Q_1+Q_2=QimpliesQ_1=(Q)/(3)& Q_2= (2Q)/(3)`


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