A capacitor of capacitance C is charged to a constant potential difference V and then connected in series with an open key and a pure resistor r. At tiem t=0 , the key is closed. If I is current at time t=0, aplot of log I against t is shown as in the graph (I) . Latter on of the parameters, i.e. V,R and C is changed, keeping the other two constant and graph (2) is recoded. Then -

A capacitor of capacitance C is charged to a constant potential differ

1.	A capacitor of capacitance C is charged to a constant potential difference V and then connected in series with an open key and a pure resistor r. At tiem t=0 , the key is closed. If I is current at time t=0, aplot of log I against t is shown as in the graph (I) . Latter on of the parameters, i.e. V,R and C is changed, keeping the other two constant and graph (2) is recoded. Then -
Answer» C is reduced C is increased R is reduced R is increased Solution : It is discharging of capactior `I=(E)/(R)e^(-t//RC)` log `I="log"(E)/(R)-(t)/(RC)` INTERCEPT is constant `RARR` E & R constant \|slope\| dercrease `rArrCuarr`

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