A capacitor of capacitnace C is charged to a potential difference V and then disconnected from the battery. Now it is connected to an inductor of inductance L at t=0. ThenA. Energy stored in capacitor and inductor will be equal at time `t=(pi)/(2)sqrtLC`B. Potential difference across inductor will be `(V)/(2)` at time `t=(pi)/(3)sqrtLC`C. The rate of increase of energy in magnetic field will be maximum at `(pi)/(4)sqrtLC`D. When the potentail difference across the capacitor `sqrt(((3C)/(L)))`

A capacitor of capacitnace C is charged to a potential difference V an

1.	A capacitor of capacitnace C is charged to a potential difference V and then disconnected from the battery. Now it is connected to an inductor of inductance L at t=0. ThenA. Energy stored in capacitor and inductor will be equal at time `t=(pi)/(2)sqrtLC`B. Potential difference across inductor will be `(V)/(2)` at time `t=(pi)/(3)sqrtLC`C. The rate of increase of energy in magnetic field will be maximum at `(pi)/(4)sqrtLC`D. When the potentail difference across the capacitor `sqrt(((3C)/(L)))`
Answer» Correct Answer - B::C::D

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